4/33x[21/8÷3/4÷(5/6÷20/3)-(27/8÷3/4)+1/2]
4/33x[21/8÷3/4÷(5/6÷20/3)-(27/8÷3/4)+1/2]
4/33x[21/8÷3/4÷(5/6÷20/3)-(27/8÷3/4)+1/2]
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$\frac{4}{33}×\big[\frac{21}{8}÷\frac{3}{4}÷\big(\frac{5}{6}÷\frac{20}{3}\big)-\big(\frac{27}{8}÷\frac{3}{4}\big)+\frac{1}{2}\big]=$
$=\frac{4}{33}×\big[\frac{21}{8}×\frac{4}{3}÷\big(\frac{5}{6}×\frac{3}{20}\big)-\big(\frac{27}{8}×\frac{4}{3}\big)+\frac{1}{2}\big]=$
$=\frac{4}{33}×\big[\frac{7}{2}×\frac{1}{1}÷\big(\frac{1}{2}×\frac{1}{4}\big)-\big(\frac{9}{2}×\frac{1}{1}\big)+\frac{1}{2}\big]=$
$=\frac{4}{33}×\big[\frac{7}{2}÷\frac{1}{8}-\frac{9}{2}+\frac{1}{2}\big]=$
$=\frac{4}{33}×\big[\frac{7}{2}×8-\frac{9}{2}+\frac{1}{2}\big]=$
$=\frac{4}{33}×\big[\frac{7}{1}×4-\frac{9}{2}+\frac{1}{2}\big]=$
$=\frac{4}{33}×\big[28-\frac{9}{2}+\frac{1}{2}\big]=$
$=\frac{4}{33}×\big[\frac{56-9+1}{2}\big]=$
$=\frac{4}{33}×\frac{48}{2}=$
$=\frac{2}{33}×\frac{48}{1}=$
$=\frac{96}{33}=$
$=\frac{32}{11}=$