N° 141

((3 - 13/11)/(2/3 - 4/11) - 3/5)·8/3 - (4/3/(1/3) - 4 + 16/15)=

=(20/11/(10/33) - 3/5)·8/3 - (4/3/(1/3) - 4 + 16/15)=

=(6 - 3/5)·8/3 - (4 - 4 + 16/15)=

=27/5·8/3 - 16/15=

=216/5/3 - 16/15=

=72/5 - 16/15=

=40/3

{[(3-13/11)÷(2/3-4/11)]-3/5}×8/3-(4/3÷1/3-4+16/15)

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$\big\{\big[\big(3-\frac{13}{11}\big)÷\big(\frac{2}{3}-\frac{4}{11}\big)\big]-\frac{3}{5}\big\}×\frac{8}{3}-\big(\frac{4}{3}÷\frac{1}{3}-4+\frac{16}{15}\big)=$

$=\big\{\big[\big(\frac{33-13}{11}\big)÷\big(\frac{22-12}{33}\big)\big]-\frac{3}{5}\big\}×\frac{8}{3}-\big(\frac{4}{3}×3-4+\frac{16}{15}\big)=$

$=\big\{\big[\frac{20}{11}÷\frac{10}{33}\big]-\frac{3}{5}\big\}×\frac{8}{3}-\big(4-4+\frac{16}{15}\big)=$

$=\big\{\big[\frac{20}{11}×\frac{33}{10}\big]-\frac{3}{5}\big\}×\frac{8}{3}-\frac{16}{15}=$

$=\big\{\big[\frac{2}{1}×\frac{3}{1}\big]-\frac{3}{5}\big\}×\frac{8}{3}-\frac{16}{15}=$

$=\big\{6-\frac{3}{5}\big\}×\frac{8}{3}-\frac{16}{15}=$

$=\big\{\frac{30-3}{5}\big\}×\frac{8}{3}-\frac{16}{15}=$

$=\frac{27}{5}×\frac{8}{3}-\frac{16}{15}=$

$=\frac{9}{5}×\frac{8}{1}-\frac{16}{15}=$

$=\frac{72}{5}-\frac{16}{15}=$

$=\frac{216-16}{15}=$

$=\frac{200}{15}=$

$=\frac{40}{3}$