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1

(5/3-1)-(1/3-1/6)+5/10-1=

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2

$(2/3)-(1/6)+5/10-1$
$3/6+1/2-1$
$1/2+1/2-1$
$1-1$
$0$



1

(5/3-1)-(1/3-1/6)+5/10-1=

=============================================

$\big(\frac{5}{3}-1\big)-\big(\frac{1}{3}-\frac{1}{6}\big)+\frac{5}{10}-1=$

$= \big(\frac{5-3}{3}\big)-\big(\frac{2-1}{6}\big)+\frac{1}{2}-1=$

$= \frac{2}{3}-\frac{1}{6}+\frac{1}{2}-1=$

$= \frac{4-1+3-6}{6}=$

$=\frac{0}{6}=$

$=0$



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