Spiegare i passaggi.
1 / (x^2 +3x) = 1 / [x * (x + 3)] =
= [1/x - 1 /(x +3)] / 3;
∫[1 / [x * (x + 3)] dx = 1/3 * ∫[1/x - 1 /(x +3)] dx =
= 1/3 * ∫1/x dx - 1/3 * ∫[1/(x + 3)] dx =
= 1/3 * ln|x| - 1/3 ln |x+3| + C.
Ciao @alby
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