$1+\dfrac{5}{8}x+\dfrac{5(x-3)}{12}-\dfrac{3(x-2)}{4}= -\dfrac{x+6}{8}+\dfrac{1}{3}$
mcm dei denominatori = 24 quindi:
$24+15x+10(x-3)-18(x-2) = -3(x+6)+8$
$24+15x+10x-30-18x+36 = -3x-18+8$
$7x+30 = -3x-10$
$7x+3x = -10-30$
$10x = -40$
$x= -\dfrac{40}{10}$
$x= -4$
applicando il secondo principio di equivalenza
24 + 15 x + 10 (x - 3 ) - 18 ( x - 2 ) = -3 ( x + 6 ) + 8
24 + 15 x + 10 x - 30 - 18 x + 36 = - 3x - 18 + 8
7x + 30 = - 3 x - 10
7x + 3x = -10 - 30
10x = -40
x = -40/10 = -4