Geometria

A=d^2/2=162cm2   L=radquad 162=12,72  perim=12,72*4=50,9cm

lato L = d/√2 = d*√2 /2 = 9√2

area A = L^2 = 81*2 = 162 dm^2

perimetro 2p = 9√2 *4 = 36√2 dm (50,91)

La diagonale di un quadrato misura 18 dm. Calcola il perimetro e l'area del quadrato.

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Perimetro $2p= 4·l = 4×\dfrac{d}{\sqrt2} = 4×\dfrac{18}{\sqrt2} = 4×9\sqrt2 ~dm~~(≅ 50,91~dm)$;

area $A= l^2 = \bigg(\dfrac{d}{\sqrt2}\bigg)^2 = \dfrac{d^2}{2} = \dfrac{18^2}{2} = 162~dm^2$.