Mi potreste aiutare con i passaggi da fare. Grazie
Espressione nr 141 A e B
0,(6) = 2/3 ; 0,(5) = 5/9
25/24-7/8+2/3-0,9*5/9
(25-21)/24+2/3-1/2
1/6+2/3-1/2
(1+4-3)/6 = 2/6 = 1/3
0,1(6) = 1/6 ; 0,(1) = 1/9
(5+4*1/6)*9
45+6 = 51
@remanzini_rinaldo Scusa se intervengo ma, se non ho sbagliato io, riguarda la seconda espressione perché dovrebbe tornare 51. Saluti.
25/24 - 7/8 + 6/9 - 9/10 * 5/9=
= 25/24 - 7/8 + 2/3 - 1/2 =
mcm = 2^3 * 3 = 24;
= 25/24 - 21/24 + 16/24 - 12/24 =
= (25 - 21 + 16 -12) /24 = 8/24; dividendo per 8:
= 1/3.
(4/9 : 2/9 + 5/10) : 325/100;
[3,25 = 325 / 100 =325 : 5 / (100 : 5) = 13/4].
(4/9 * 9/2 + 1/2) : 13 / 4 =
= (2 + 1/2) * 4/13 =
= (4/2 + 1/2) * 4/13 =
= 5/2 * 4/13 = 10/13.
(5 + 4 * (16 - 1)/90 ) : 1/9=
(5 + 4 *15/90) : 1/9 =
= (5 + 4 * 1/6) : 1/9 =
= (5 + 2/3) * 9/1 =
= (15/3 + 2/3) * 9/1 =
= 17/3 * 9 = 17 * 3 = 51.
@giustot ciao
141A)
$\frac{25}{24} - \frac{7}{8} + 0,(6) - 0,9×0,(5) =$
$\frac{25}{24} - \frac{7}{8} + \frac{6-0}{9} - \frac{9}{10}×\frac{5-0}{9} =$
$=\frac{25}{24} - \frac{7}{8} + \frac{6}{9} - \frac{9}{10}×\frac{5}{9} =$
$=\frac{25}{24} - \frac{7}{8} + \frac{2}{3} - \frac{1}{2}×\frac{1}{1} =$
$=\frac{25}{24} - \frac{7}{8} + \frac{2}{3} - \frac{1}{2}=$ $(mcm= 24)$:
$=\frac{25-21+16-12}{24} =$
$= \frac{8}{24}=$
$= \frac{1}{3}$.
141B)
$(5 + 4×0,1(6)) : 0,(1) =$
$= (5 + 4×\frac{16-1}{90}): \frac{1-0}{9} =$
$= (5 + 4×\frac{15}{90}): \frac{1}{9} =$
$= (5 + 4×\frac{1}{6})×9 =$
$= (5 + 2×\frac{1}{3})×9 =$
$= (5 + \frac{2}{3})×9 =$
$= (\frac{15+2}{3})×9 =$
$= \frac{17}{3}×9 =$
$= \frac{17}{1}×3 =$
$= 51$.