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Potenze di uguale base, ma segno diverso:

(- 7/6)^5 : (+ 7/6)^2 : (+ 7/6)^1 * (- 7/6)^3 : (7/6)^4 l=

   (-)       :    (+)            :  (+)       *    (-)        :   (+)  =  (+ 7/6); (base)

= (+ 7/6)^(5 - 2 - 1 + 3 - 4) = (7/6)^1

- (1/2)^6 : (1/2)^5  * (1/2)^1 = - (1/2)^(6 - 5 + 1) = - (1/2)^2;

(7/6) - (1/2)^2 = 

= 7/6 - 1/4 =

= 14/12 - 3/12 = 11/12.

Ciao  @eliacangi

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$\small \left(-\dfrac{7}{6}\right)^5÷\left(\dfrac{7}{6}\right)^2÷\left(\dfrac{7}{6}\right)·\left(-\dfrac{7}{6}\right)^3÷\left(\dfrac{7}{6}\right)^4-\left(\dfrac{1}{2}\right)^6÷\left(\dfrac{1}{2}\right)^5·\left(\dfrac{1}{2}\right) =$

$\small = \left(\dfrac{7}{6}\right)^{5-2-1+3-4}-\left(\dfrac{1}{2}\right)^{6-5+1}=$

$\small = \left(\dfrac{7}{6}\right)^1-\left(\dfrac{1}{2}\right)^2=$

$\small = \dfrac{7}{6}-\dfrac{1}{4}=$

$\small = \dfrac{14-3}{12}=$

$\small = \dfrac{11}{12}$

(7/6)^((5+3-(2+1+4)) - (1/2)^(6+1-5)

(7/6)^1 - (1/2)^2

7/6-1/4

(14-3)/12

11/12