324)
$\frac{[(-3a^3)^2(-2a^2)+10a^8]^2}{(4a^5)^2-2a^6}$ =
= $\frac{[9a^6(-2a^2)+10a^8]^2}{16a^{10}-2a^6}$ =
= $\frac{[-18a^8+10a^8]^2}{16a^{10}-2a^6}$ =
= $\frac{[-8a^8]^2}{16a^{10}-2a^6}$ =
= $\frac{64a^{16}}{16a^{10}-2a^6}$
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