1/2 - 1/3 = 1/6
16/9 - 1/3 = 13/9
x^2 = 1/6·(13/9)
x^2 = 13/54-----> x = - √78/18 ∨ x = √78/18
x : (1/6) = 5/x
x^2 = 5/6
x = √5 / √6
$x : \big(\frac{1}{2}-\frac{1}{3}\big) = \big(\frac{16}{9}-\frac{1}{3}\big) : x$
$x : \big(\frac{3-2}{6}\big) = \big(\frac{16-3}{9}\big) : x$
$x : \frac{1}{6} = \frac{13}{9} : x$ moltiplica tra loro gli estremi e i medi:
$x×x = \frac{1}{6}×\frac{13}{9}$
$x^2 = \frac{13}{54}$ radice quadrata di ambo le parti:
$\sqrt{x^2} = \sqrt{\frac{13}{54}}$
$x= \frac{\sqrt{78}}{18}~→(≅ 0,490653)$.
Se invece quel 16/9 è un 16/3 fai:
$x : \big(\frac{1}{2}-\frac{1}{3}\big) = \big(\frac{16}{3}-\frac{1}{3}\big) : x$
$x : \big(\frac{3-2}{6}\big) = \frac{15}{3} : x$
$x : \frac{1}{6} = 5 : x$
$x×x = \frac{1}{6}×5$
$x^2 = \frac{5}{6}$
$\sqrt{x^2} = \sqrt{\frac{5}{6}}$
$x= \frac{\sqrt{30}}{6} ~→(0,912871)$.