x^2/α + y^2/β = 1
α > β
α = a^2
β = b^2
ε = γ/α = (α - β)/α = e^2 = 2/3
Quindi sistema:
{(- √3)^2/α + (- √2)^2/β = 1 (passa da [- √3, - √2])
{(α - β)/α = 2/3
Risolvo :
{3/α + 2/β = 1
ottengo: [α = 9 ∧ β = 3]
x^2/9 + y^2/3 = 1
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