Notifiche
Cancella tutti

Chi puo aiutarmi in questa espressione

  

0
IMG 20231109 215703 533
Autore
1 Risposta



1
image

============================================================

 

$\big(\frac{1}{3}\big)^2·\big(-\frac{1}{3}\big)^3·(3^3)·(-3)^5 ÷ \big[\big(-\frac{1}{3}\big)^3\big]^2÷(-3)^7 =$

$= \big(-\frac{1}{3}\big)^{2+3}·(-3)^{3+5} ÷ \big(-\frac{1}{3}\big)^{3·2}÷(-3)^7 =$

$= \big(-\frac{1}{3}\big)^5·(3)^8 ÷ \big(-\frac{1}{3}\big)^6÷(-3)^7 =$

$= (-3)^{-5}·(3)^8÷(-3)^{-6}÷(-3)^7=$

$= -(3)^{-5+8-(-6)-7}=$

$= -(3)^{3+6-7}=$

$= -(3)^2=$

$= -9$

 

 

 

 



Risposta
SOS Matematica

4.6
SCARICA