Buon giovedì a tutti! Ecco un esercizio di algebra che ho avuto difficoltà a svolgere, spero mi possiate aiutare!

(7/3 - 11/5)/(- 4/5)^2 + (29/24 - 1)^3/(2 - 43/24)^2 - 8/3·(5/4 + 3/8 - 3/2)=

=2/15/(16/25) + (5/24)^3/(5/24)^2 - 8/3·(1/8)=

=5/24 + 5/24 - 1/3=

=1/12

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Buon giovedì anche a te.

$\small \left(\dfrac{7}{3}-\dfrac{11}{5}\right) : \left(-\dfrac{4}{5}\right)^2+\left(\dfrac{29}{24}-1\right)^3 : \left(2-\dfrac{43}{24}\right)^2-\dfrac{8}{3}·\left(\dfrac{5}{4}+\dfrac{3}{8}-\dfrac{3}{2}\right)=$

$\small =\left(\dfrac{35-33}{15}\right) : \dfrac{16}{25}+\left(\dfrac{29-24}{24}\right)^3 : \left(\dfrac{48-43}{24}\right)^2-\dfrac{8}{3}·\left(\dfrac{10+3-12}{8}\right)=$

$\small =\dfrac{2}{15}·\dfrac{25}{16}+\left(\dfrac{5}{24}\right)^3 : \left(\dfrac{5}{24}\right)^2-\dfrac{8}{3}·\dfrac{1}{8}=$

$\small =\dfrac{\cancel2^1}{\cancel{15}_3}·\dfrac{\cancel{25}^5}{\cancel{16}_8}+\left(\dfrac{5}{24}\right)^{3-2}-\dfrac{\cancel8^1}{3}·\dfrac{1}{\cancel8_1}=$

$\small =\dfrac{1}{3}·\dfrac{5}{8}+\left(\dfrac{5}{24}\right)^1-\dfrac{1}{3}·\dfrac{1}{1}=$

$\small =\dfrac{5}{24}+\dfrac{5}{24}-\dfrac{1}{3}=$

$\small =\dfrac{10}{24}-\dfrac{1}{3}=$

$\small =\dfrac{\cancel{10}^5}{\cancel{24}_{12}}-\dfrac{1}{3}=$

$\small =\dfrac{5}{12}-\dfrac{1}{3}=$

$\small =\dfrac{5-4}{12}=$

$\small =\dfrac{1}{12}\quad(=0,08\overline3).$