Scusate, mi potete gentilmente aiutare con questa espressione per favore? Grazie
(28/99 - (125 - 1)/990 - 3/99)/((93 - 9)/90)=
=(28/99 - 62/495 - 1/33)/(14/15)
Il numeratore vale:
28/99 - 62/495 - 1/33 = 7/55
(i conti li fai tu)
quindi:
7/55·(15/14) = 3/22
$(0,\overline{28}-0,1\overline{25}-0,\overline{03}) : 0,9\overline3=$
$= \left(\dfrac{28-0}{99}-\dfrac{125-1}{990}-\dfrac{3-0}{99}\right) : \dfrac{93-9}{90}=$
$= \left(\dfrac{28}{99}-\dfrac{124}{990}-\dfrac{3}{99}\right) : \dfrac{84}{90}=$
$= \left(\dfrac{28}{99}-\dfrac{\cancel{124}^{62}}{\cancel{990}_{495}}-\dfrac{\cancel3^1}{\cancel{99}_{33}}\right) : \dfrac{\cancel{84}^{14}}{\cancel{90}_{15}}=$
$= \left(\dfrac{140-62-15}{495}\right) : \dfrac{14}{15}=$
$= \dfrac{63}{495} · \dfrac{15}{14}=$
$= \dfrac{\cancel{63}^7}{\cancel{495}_{55}} · \dfrac{15}{14}=$
$= \dfrac{7}{55} · \dfrac{15}{14}=$
$= \dfrac{\cancel7^1}{\cancel{55}_{11}}·\dfrac{\cancel{15}^3}{\cancel{14}_2}=$
$= \dfrac{1}{11}·\dfrac{3}{2}=$
$=\dfrac{3}{22}$