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$\small \left(ab-\dfrac{2}{3}ab\right)b^3 -a\left(-b^2\right)^3 : \left(-\dfrac{1}{3}b\right)^2+\dfrac{2}{3}ab^4 =$

$\small =\left(\dfrac{3-2}{3}ab\right)b^3 -a\left(-b^{2×3}\right) : \dfrac{1}{9}b^2+\dfrac{2}{3}ab^4 =$

$\small =\left(\dfrac{1}{3}ab\right)b^3 -a\left(-b^6\right) · 9b^{-2}+\dfrac{2}{3}ab^4 =$

$\small =\dfrac{1}{3}ab^4 +ab^6 · 9b^{-2}+\dfrac{2}{3}ab^4 =$

$\small =\dfrac{1}{3}ab^4 +9ab^{6+(-2)} +\dfrac{2}{3}ab^4 =$

$\small =\dfrac{1}{3}ab^4 +9ab^{6-2} +\dfrac{2}{3}ab^4 =$

$\small =\dfrac{1}{3}ab^4 +9ab^4 +\dfrac{2}{3}ab^4 =$

$\small = \dfrac{1+27+2}{3}ab^4 =$

$\small = \dfrac{\cancel{30}^{10}}{\cancel3_1}ab^4 =$

$\small = 10ab^4$

@gramor 👍👌👍



1

(1 - 2/3) ab*b^3 - a *(-b^6) : [(-1/3)^2 * b^2] + 2/3 ab^4 =

= 1/3 ab^4 + ab^6 : 1/9 b^2 + 2/3 ab^4 =

= 1/3 ab^4 + (1 : 1/9) ab^4 + 2/3 ab^4 =

= (1/3 + 1*9 + 2/3) ab^4 =

= (1 + 9) ab^4 =

= 10 ab^4

@eidosm grazie mille



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