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Question

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marus76 · Accepted Answer

[attach]48576[/attach] [attach]48578[/attach]

LucianoP · Answer

2·(x^2 - 1) + (- x^3 + 6·x^2 - 12·x + 8) + 12·x = 2·(4·x^2 - 1) - x^3 + 8

- x^3 + 8·x^2 + 6 = - x^3 + 8·x^2 + 6

0·x = 0 INDETERMINATA

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3/5·x - 2/3 = 2/3 - 2/5·x + 5/3

3/5·x + 2/5·x = 4/3 + 5/3

x = 3

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(@lucianop)

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