I numeri relativi Algebra

((- 1/5 + 3/2 - 1/10)·(15/4)/(1/4) - 1)·(13/17) + 1=

=(6/5·(15/4)/(1/4) - 1)·(13/17) + 1=

=(9/2/(1/4) - 1)·(13/17) + 1=

=(18 - 1)·(13/17) + 1=

=17·(13/17) + 1=

=13 + 1 = 14

Parentesi tonda:  (- 1/5 + 3/2 - 1/10);  mcm (5; 2; 10) = 10;

{[(- 2/10 + 15/10 - 1/10)  * 15/4] : 1/4 - 1} * 13/17 + 1 =

= {[ + 12/10 * 15/4 ] : 1/4 - 1} * 13/17 + 1 = 

12/10 si semplifica per 2, diventa 6/5

= { [6/5 * 15/4] : 1/4 - 1} * 13/17 + 1 = 

moltiplicazione:

6 * 15 / (5 * 4) = 3 * 3 / (1 * 2) = 9/2.

= { 9/2 * 4/1 - 1} * 13/17 + 1 = 

= {18/1 - 1} * 13/17 + 1 = 

= {18 - 1} * 13/17 + 1 = 

= 17 * 13/17 + 1 = 

= 13 + 1 = + 14.

@lolik  ciao.

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$\small \left\{\left[\left(-\dfrac{1}{5}+\dfrac{3}{2}-\dfrac{1}{10}\right)·\dfrac{15}{4}\right]÷\dfrac{1}{4}-1\right\}·\dfrac{13}{17}+1 =$

$\small = \left\{\left[\left(\dfrac{-2+15-1}{10}\right)·\dfrac{15}{4}\right]·4-1\right\}·\dfrac{13}{17}+1 =$

$\small = \left\{\left[\dfrac{\cancel{12}^6}{\cancel{10}_5}·\dfrac{15}{4}\right]·4-1\right\}·\dfrac{13}{17}+1 =$

$\small = \left\{\left[\dfrac{\cancel6^3}{\cancel5_1}·\dfrac{\cancel{15}^3}{\cancel4_2}\right]·4-1\right\}·\dfrac{13}{17}+1 =$

$\small = \left\{\left[\dfrac{3}{1}·\dfrac{3}{2}\right]·4-1\right\}·\dfrac{13}{17}+1 =$

$\small = \left\{\dfrac{9}{\cancel2_1}·\cancel4^2-1\right\}·\dfrac{13}{17}+1 =$

$\small = \left\{9·2-1\right\}·\dfrac{13}{17}+1 =$

$\small = \left\{18-1\right\}·\dfrac{13}{17}+1 =$

$\small = \cancel{17}^1·\dfrac{13}{\cancel{17}_1}+1 =$

$\small = 1·\dfrac{13}{1}+1 =$

$\small = 13+1 =$

$\small = 14$

{[(-2+15-1/10)*15/4]:1/4-1}*13/17+1=

={[6/5*15/4]:1/4-1}*13/17+1=

={9/2*4-1}*13/7+1=

=17*13/17+1=

=13+1=+14

Ciao @Lolik