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espressione n° 80

  

0

[(2-1)x7+5] ÷ [3-(1-1)] + [15-3x(1+2)]

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2

((2 - 1)·7 + 5)/(3 - (1 - 1)) + (15 - 3·(1 + 2))=

=12/3 + (15 - 9)= 4 + 6 = 10



2

[(2-1)x7+5] ÷ [3-(1-1)] + [15-3x(1+2)]

[1x7+5]:[3-0]+[15-3x3]
12:3+6= 4+6= 10



2

$[(2-1)×7+5] ÷ [3-(1-1)]+[15-3(1+2)] $ =

= $[1×7+5] ÷ [3-0]+[15-3×3] $ =

= $[7+5] ÷ 3 +[15-9] $ =

= $12 ÷ 3 + 6$ =

= $4+6$ =

= $10$ 



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