a)
64 = 2^6
16 = 2^4
8 = 2^3
Quindi: 2^6·2^4·2^3 = 2^13 anelli
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b)
2^13/(8·32) =2^13/(2^3·2^5) =2^5 = 32 pacchi
(147)
a)
64 = 8*8 = 2^3*2^3 = 2^(3+3) = 2^6
16 = 4*4 = 2^2*2^2 = 2^(2+2) = 2^4
8 = 2^2*2 = 2^(2+1) = 2^3
64*16*8 = 2^(6+4+3) = 2^13
b)
32 = 8*4 = 2^3*2^2 = 2^(3+2) = 2^5
2^13 / (2^3*2^5) = 2^13 / 2^(3+5) = 2^(13-8) = 2^5 = 32
147)
a) Totale anelli $= 2^3×2^4×2^6 = 2^{3+4+6} = 2^{13}$;
b) n° pacchi $= 2^{13} : 2^5 : 2^3 = 2^{13-5-3} = 2^5 = 32$.