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problema 147, urgente!! graziee

  

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4

a)

64 = 2^6

16 = 2^4

8 = 2^3

Quindi: 2^6·2^4·2^3 = 2^13 anelli

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b)

2^13/(8·32) =2^13/(2^3·2^5) =2^5 = 32 pacchi



2

(147)

a)

64 = 8*8 = 2^3*2^3 = 2^(3+3) = 2^6

16 = 4*4 = 2^2*2^2 = 2^(2+2) = 2^4

8 = 2^2*2 = 2^(2+1) = 2^3

64*16*8 = 2^(6+4+3) = 2^13 

 

b) 

32 = 8*4 = 2^3*2^2 = 2^(3+2) = 2^5

2^13 / (2^3*2^5) = 2^13 / 2^(3+5) = 2^(13-8) = 2^5 = 32 



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147)

a) Totale anelli $= 2^3×2^4×2^6 = 2^{3+4+6} = 2^{13}$;

b) n° pacchi $= 2^{13} : 2^5 : 2^3 = 2^{13-5-3} = 2^5 = 32$.



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