Notifiche
Cancella tutti

N. 20

  

0

(6+5×2)-{[7×(4-3)]×3-5}+3=

Autore
2 Risposte



0

(6+5×2)-{[7×(4-3)]×3-5}+3=

$(6+10)-{[7×1]×(-2)}+3=$

$16-{[7×(-2)}+3=$

$16-{-14}+3=$

$16+14+3=33$



0

$(6+5×2)-\{[7×(4-3)]×3-5\}+3$ =

= $(6+10)-\{[7×1]×3-5\}+3$ =

= $16-\{7×3-5\}+3$ =

= $16-\{21-5\}+3$ =

= $16-16+3$ =

= $3$



Risposta