(6+5×2)-{[7×(4-3)]×3-5}+3=
(6+5×2)-{[7×(4-3)]×3-5}+3=
(6+5×2)-{[7×(4-3)]×3-5}+3=
$(6+10)-{[7×1]×(-2)}+3=$
$16-{[7×(-2)}+3=$
$16-{-14}+3=$
$16+14+3=33$
$(6+5×2)-\{[7×(4-3)]×3-5\}+3$ =
= $(6+10)-\{[7×1]×3-5\}+3$ =
= $16-\{7×3-5\}+3$ =
= $16-\{21-5\}+3$ =
= $16-16+3$ =
= $3$