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[Risolto] N° 178

  

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{[(24-7x3)^4÷(-3)^2]^3÷(3)^6}x[15-(16+6)]^2-43+7

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178)

$\{[(24-7×3)^4÷(-3)^2]^3÷(3)^6\}×[15-(16+6)]^2-43+7=$

$=\{[(24-21)^4÷(-3)^2]^3÷3^6\}×[15-22]^2-43+7=$

$= \{[3^4÷(-3)^2]^3÷3^6 \}×[-7]^2-43+7 =$

$= \{[(-3)^{4-2}]^3÷3^6 \}×49-43+7 =$

$= \{[(-3)^2]^3÷3^6 \}×49-43+7 =$

$= \{(-3)^{2×3}÷3^6 \}×49-43+7 =$

$= \{(-3)^6÷3^6 \}×49-43+7 =$

$= (-3)^{6-6}×49-43+7 =$

$= (-3)^0×49-43+7 =$

$= 1×49-43+7 =$

$= 49-43+7=$

$=13$



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