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Mi aiutate cortesemente a risolvere esp. con potenze di numeri relativi

  

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[(- 3/4)^-4 : [(- 3/4)^(2 - 3 + 2)] =

= [(- 3/4)^-4 : [(- 3/4)^1] =

= [(- 3/4)^(- 4 - 1)] = (- 3/4)^-5 =

= (- 4/3)^5.

Ciao @r

@mg 👍👌🌹👍



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$\small \left[\left(-\dfrac{3}{4}\right)^{-2}\right]^2÷\left[\left(-\dfrac{3}{4}\right)^2·\left(-\dfrac{3}{4}\right)^{-3}÷\left(-\dfrac{3}{4}\right)^{-2}\right] =$

$\small = \left(-\dfrac{3}{4}\right)^{-2·2}÷\left[\left(-\dfrac{3}{4}\right)^{2+(-3)-(-2)}\right] =$

$\small = \left(-\dfrac{3}{4}\right)^{-4}÷\left(-\dfrac{3}{4}\right)^{2-3+2} =$

$\small = \left(-\dfrac{4}{3}\right)^4÷\left(-\dfrac{3}{4}\right)^1 =$

$\small = \left(-\dfrac{4}{3}\right)^4·\left(-\dfrac{4}{3}\right)^1 =$

$\small = \left(-\dfrac{4}{3}\right)^{4+1} =$

$\small = \left(-\dfrac{4}{3}\right)^5 $

 

$\small =\left(-\dfrac{1024}{243}\right).$

@gramor 👍👌👍



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