INGLESE Find the centripetal acceleration of the Earth in its yearly orbit around the Sun. Assume that the Earth has a circular motion of radius $1.50 \cdot 10^{11} \mathrm{~m}$ and remember that the orbital period is 365 days.
$\left[5.95 \cdot 10^{-3} \mathrm{~m} / \mathrm{s}^2\right]$
11
punti
Livello 0
12972
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Livello 7
centripetal acceleration ac = ω^2*r
ac = (6,2832/(3600*24*365))^2*1,50*10^11 = 5,954*10^-3 m/s^2
142436
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Genius III
