grazie a chi mi risponderà
$[(0,2\overline7+0,\overline1) ÷ (1,\overline3+1)+1,2·(3,5-3,\overline3)]÷(2,2-2)=$
$=\big[\big(\frac{27-2}{90}+\frac{1-0}{9}\big) ÷\big(\frac{13-1}{9}+1\big)+\frac{12}{10}·\big(\frac{35}{10}-\frac{33-3}{9}\big)\big]÷\big(\frac{22}{10}-2\big)=$
$=\big[\big(\frac{25}{90}+\frac{1}{9}\big) ÷\big(\frac{12}{9}+1\big)+\frac{6}{5}·\big(\frac{7}{2}-\frac{30}{9}\big)\big]÷\big(\frac{11}{5}-2\big)=$
$=\big[\big(\frac{5}{18}+\frac{1}{9}\big) ÷\big(\frac{4}{3}+1\big)+\frac{6}{5}·\big(\frac{7}{2}-\frac{10}{3}\big)\big]÷\big(\frac{11-10}{5}\big)=$
$=\big[\big(\frac{5+2}{18}\big) ÷\big(\frac{4+3}{3}\big)+\frac{6}{5}·\big(\frac{21-20}{6}\big)\big]÷\frac{1}{5}=$
$=\big[\frac{7}{18} ÷\frac{7}{3}+\frac{6}{5}·\frac{1}{6}\big]·5=$
$=\big[\frac{7}{18}·\frac{3}{7}+\frac{1}{5}·\frac{1}{1}\big]·5=$
$=\big[\frac{1}{6}·\frac{1}{1}+\frac{1}{5}\big]·5=$
$=\big[\frac{1}{6}+\frac{1}{5}\big]·5=$
$=\big[\frac{5+6}{30}\big]·5=$
$=\frac{11}{30}·5=$
$=\frac{11}{6}·1=$
$=\frac{11}{6}=$