numero 272.non mi viene giusta
272)
$\small 2x^3-\left(3x^5\right) : \left(-2x\right)^2+\left(\dfrac{3}{2}x\right)^2·\left(\dfrac{2}{9}x\right)+\left[2x^5+\left(-x^2\right)^2·x\right] : \left(-3x^2\right) =$
$\small = 2x^3-\left(3x^5\right) : 4x^2+\dfrac{\cancel9^1}{\cancel4_2}x^2·\dfrac{\cancel2^1}{\cancel9_1}x+\left[2x^5+x^4·x\right] : \left(-3x^2\right) =$
$\small = 2x^3-\dfrac{3}{4}x^3 +\dfrac{1}{2}x^2·x+\left[2x^5+x^5\right] : \left(-3x^2\right) =$
$\small = 2x^3-\dfrac{3}{4}x^3 +\dfrac{1}{2}x^3+3x^5 : \left(-3x^2\right) =$
$\small = 2x^3-\dfrac{3}{4}x^3 +\dfrac{1}{2}x^3+\cancel3x^5 : \left(-\cancel3x^2\right) =$
$\small = 2x^3-\dfrac{3}{4}x^3 +\dfrac{1}{2}x^3-x^3 =$
$\small = \left(2-\dfrac{3}{4}+\dfrac{1}{2}-1 \right)x^3=$
$\small = \left(\dfrac{8-3+2-4}{4} \right)x^3=$
$\small = \dfrac{3}{4}x^3$