Calcola l'espressione con i radicali

√(√0.01 + √0.81) + (15/8 + (-8)^(1/3))^(1/3)=

=√(√(1/100) + √(81/100)) + (15/8 - 2)^(1/3)=

=√(1/10 + 9/10) + (- 1/8)^(1/3)=

=√1 - 1/2 = 1/2

radice quadrata(0,01) = radice(1/100) = 1/10 = 0,1;

radice quadrata(0,81) = radice(81/100) = 9/10 = 0,9;

radicecubica(-8) = - 2;

radice quadrata(0,1 + 0,9) + radicecubica[15/8 + (-2)];

radice quadrata(1) + radicecubica[15/8 - 16/8]=

= 1 + radicecubica[- 1/8] =

= 1 - 1/2 =

= 2/2 - 1/2 = 1/2.

@alby  ciao.

============================================================

$\small \sqrt{\sqrt{0,01}+\sqrt{0,81}}+\sqrt[3]{\dfrac{15}{8}+\sqrt[3]{-8}}=$

$\small =\sqrt{\sqrt{\dfrac{1}{100}}+\sqrt{\dfrac{81}{100}}}+\sqrt[3]{\dfrac{15}{8}+(-2)}=$

$\small =\sqrt{\dfrac{1}{10}+\dfrac{9}{10}}+\sqrt[3]{\dfrac{15}{8}-2}=$

$\small =\sqrt{\dfrac{10}{10}}+\sqrt[3]{\dfrac{15-16}{8}}=$

$\small =\sqrt1+\sqrt[3]{-\dfrac{1}{8}}=$

$\small =1+\left(-\dfrac{1}{2}\right)=$

$\small =1-\dfrac{1}{2}=$

$\small =\dfrac{2-1}{2}= \dfrac{1}{2}$