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35)
$\dfrac{a(2b+b)}{2ab}$ per $[a= -5; b= 3]$
$=\dfrac{-5(2·3+3)}{2·-5·3}=$
$=\dfrac{-5(6+3)}{-30}=$
$=\dfrac{-5·9}{-30}=$
$=\dfrac{-\cancel{45}^3}{-\cancel{30}_2}=$
$=\dfrac{3}{2}$
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