198)
$1,1·2+0,\overline1·9=$
$= \dfrac{11}{\cancel{10}_5}·\cancel2^1+\dfrac{1-0}{9}·9=$
$= \dfrac{11}{5}·1+\dfrac{1}{\cancel9_1}·\cancel9^1=$
$= \dfrac{11}{5}+\dfrac{1}{1}=$
$=\dfrac{11+5}{5}=$
$= \dfrac{16}{5}$
Home
Profilo
Menu